Today we will learn Merge sort program in C++. So before starting, we will make you know about Merge sort what actually merge sort is.

Table of Contents

## What is Merge Sort?

Merging is the process of combining two or more sorted data lists into a third list such that it is also sorted.

**For Example:** If the two sorted lists are:

**List 1:** **3 5 10 23 56**

**List 2: 4 6 9 60**

The merged list will be:

**List 3: 3 4 5 6 9 10 23 56 60**

Merge sort is based on the process of merging. It requires two sorted sub-sets to create a sorted set. In Merge sort, the elements to be sorted are divided into two equal parts. Each part is sorted and then merged. To sort each half, the same process is used.

Thus, each part is successively divided into two parts until we reach a point where the sub-part is sorted. This will happen when size=1. Since a list of size 1 is sorted, two adjacent sub-lists can be merged to create a sorted sub-lists. The merging process continues until only one list of size n is obtained.

## Merge Sort Algorithm:

Merge Sort follows the Divide and Conquer strategy

**Divide:** Divide an n element sequence into 2 subsequences of size n/2.

**Conquer:** Sort the two sequences recursively.

**Combine:** Merge the two sorted sequences into a single sequence.

This process can be done recursively as well as non recursively. We shall study the recursive method which is easier to understand.

**Recursive Function:**

void MergeSort (int a[20], int low, int high) { int mid; if(low<high) //more than one element { mid=(low + high) / 2; //Divide a into two sublists MergeSort (a,low,mid); //Sort first sub list MergeSort (a,mid+1,high); //sort second sub list Merge (a,mid,high); //Merge sorted sub lists } }

Let us consider the example of sorting 20,40,50,15,30,35,10 and 5. Initially, they are all in one list. The elements are successively divided into two sublists till we cannot divide any further i.e, we reach a sublist of size 1. The sublists are then merged to create sorted lists until all elements are in a single list.

In the example shown, each sublist has an even number of elements. However, the list may contain an odd number of elements. In such a case, one sublist will have an additional element.

Let us consider an example of sorting 5 elements

**a[5]=[67,57,2,102,33].** Here n=5. Initially **low=0** and **high=4**.

mid=(0+4)/2=2. First half=a[0]…a[2], Second half=a[3]…a[4].

Split a[0:4] into two lists a[0:2] and a[3:4] **[67,57,2] [102,33].**

**1st Step:** **MergeSort(a,0,2)**

Split a[0:2] into two lists a[0:1] and a[2:2] i.e** [67,57] [2]**

Split a[0:1] into two lists a[0:0] and a[1:1] i.e **[67] [57] [2]**

Merge a[0:0] and a[1:1] into a[0:1] i.e **[57,67] [2]**

Merge a[0:1] and a[2:2] into a[0:2] i.e **[2,57,67]**

At this stage, the first half is sorted. The same steps are carried out for the second half.

**Step 2: MergeSort(a,3,4)**

Split a[3:4] into two lists a[3:3] and a[4:4] **i.e [102] [33]**.

Merge a[3:3] and a[4:4] into a[3:4] **i.e [33,102].**

**Step 3:** Merge (a,0,4) i.e Merge a[0:2] and a[3:4] into a[0:4] which is the sorted list **[2,3,57,67,102]**

## Time Complexity of Merge Sort

The total number of iterations in Merge sort is log2n. In each iteration, n elements are merged. Hence the time complexity of Merge Sort is **O(n log2 n)**. This can be derived as follows:( Here 2 is base)

### Advantages:

Best and worst-case efficiency is O(nlog2n). Hence it is very efficient.

It is a stable sorting process.

### Disadvantages:

Additional memory is required for the merging process. It is not in-place.

## 1. Merge Sort Program in C++

Below is the program of merge sort in c where after executing the compiler will ask the user to enter the number of integers to sort. Then after entering the numbers, the compiler will print the number in the order according to merge sort algorithm.

//Learnprogramo - programmming made simple #include <iostream> using namespace std; // A function to merge the two half into a sorted data. void Merge(int *a, int low, int high, int mid) { // We have low to mid and mid+1 to high already sorted. int i, j, k, temp[high-low+1]; i = low; k = 0; j = mid + 1; // Merge the two parts into temp[]. while (i <= mid && j <= high) { if (a[i] < a[j]) { temp[k] = a[i]; k++; i++; } else { temp[k] = a[j]; k++; j++; } } // Insert all the remaining values from i to mid into temp[]. while (i <= mid) { temp[k] = a[i]; k++; i++; } // Insert all the remaining values from j to high into temp[]. while (j <= high) { temp[k] = a[j]; k++; j++; } // Assign sorted data stored in temp[] to a[]. for (i = low; i <= high; i++) { a[i] = temp[i-low]; } } // A function to split array into two parts. void MergeSort(int *a, int low, int high) { int mid; if (low < high) { mid=(low+high)/2; // Split the data into two half. MergeSort(a, low, mid); MergeSort(a, mid+1, high); // Merge them to get sorted output. Merge(a, low, high, mid); } } int main() { int n, i; cout<<"\nEnter the number of data element to be sorted: "; cin>>n; int arr[n]; for(i = 0; i < n; i++) { cout<<"Enter element "<<i+1<<": "; cin>>arr[i]; } MergeSort(arr, 0, n-1); // Printing the sorted data. cout<<"\nSorted Data "; for (i = 0; i < n; i++) cout<<"->"<<arr[i]; return 0; }

**Output:**

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